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Make smooth updates slightly more intelligent

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When processing a hint of the form "easy pkgX libX" where libX would be
a candidate for smooth updates because pkgX/testing depends on it but
pkgX/unstable does not, and there are no other reverse dependencies,
the old binary from libX can simply be dropped straight away.

Signed-off-by: Adam D. Barratt <adam@adam-barratt.org.uk>
This commit is contained in:
Adam D. Barratt 2012-04-11 21:10:28 +00:00
parent af7987c561
commit 66b7eca0f0
1 changed files with 19 additions and 2 deletions
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21
britney.py
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@ -1847,8 +1847,25 @@ class Britney(object):
# so note it for checking later # so note it for checking later
rdeps = binaries[parch][0][binary][RDEPENDS] rdeps = binaries[parch][0][binary][RDEPENDS]
if len([x for x in rdeps if x not in [y.split("/")[0] for y in bins]]) > 0: # the list of reverse-dependencies may be outdated
smoothbins.append(p) # if, for example, we're processing a hint and
# a new version of one of the apparent reverse-dependencies
# migrated earlier in the hint. walk the list to make
# sure that at least one of the entries is still
# valid
rdeps = [x for x in rdeps if x not in [y.split("/")[0] for y in bins]]
if len(rrdeps) > 0:
for dep in rrdeps:
if dep in binaries[parch][0]:
bin = binaries[parch][0][dep]
deps = []
if bin[DEPENDS] is not None:
deps.extend(apt_pkg.parse_depends(bin[DEPENDS], False))
if bin[PREDEPENDS] is not None:
deps.extend(apt_pkg.parse_depends(bin[PREDEPENDS], False))
if any(binary == entry[0] for deplist in deps for entry in deplist):
smoothbins.append(p)
break
else: else:
check.append(p) check.append(p)