Correctly get symlink name

This commit is contained in:
Iain Lane 2008-05-22 18:46:05 +01:00
parent 2f90a21dd5
commit e5cb75e9cb

View File

@ -257,7 +257,7 @@ def main():
"""
script_name = os.path.basename(__name__ or sys.argv[0])
script_name = os.path.basename(sys.argv[0])
parts = script_name.split('-')
# Copy arguments into another list for save manipulation