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import sys
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import unittest
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from collections import OrderedDict
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from . import new_pkg_universe_builder
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from britney2.installability.solver import compute_scc
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class TestInstTester(unittest.TestCase):
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def test_basic_inst_test(self):
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builder = new_pkg_universe_builder()
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universe = builder.new_package('lintian').depends_on('perl').depends_on_any_of('awk', 'mawk').\
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new_package('perl-base').is_essential().\
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new_package('dpkg').is_essential(). \
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new_package('perl').\
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new_package('awk').not_in_testing().\
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new_package('mawk').\
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build()
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pkg_lintian = builder.pkg_id('lintian')
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pkg_awk = builder.pkg_id('awk')
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pkg_mawk = builder.pkg_id('mawk')
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pkg_perl = builder.pkg_id('perl')
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pkg_perl_base = builder.pkg_id('perl-base')
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assert universe.is_installable(pkg_lintian)
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assert universe.is_installable(pkg_perl)
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assert universe.any_of_these_are_in_testing((pkg_lintian, pkg_perl))
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assert not universe.is_installable(pkg_awk)
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assert not universe.any_of_these_are_in_testing((pkg_awk,))
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universe.remove_testing_binary(pkg_perl)
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assert not universe.any_of_these_are_in_testing((pkg_perl,))
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assert universe.any_of_these_are_in_testing((pkg_lintian,))
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assert not universe.is_pkg_in_testing(pkg_perl)
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assert universe.is_pkg_in_testing(pkg_lintian)
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assert not universe.is_installable(pkg_lintian)
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assert not universe.is_installable(pkg_perl)
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universe.add_testing_binary(pkg_perl)
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assert universe.is_installable(pkg_lintian)
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assert universe.is_installable(pkg_perl)
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assert universe.reverse_dependencies_of(pkg_perl) == {pkg_lintian}
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assert universe.reverse_dependencies_of(pkg_lintian) == frozenset()
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# awk and mawk are equivalent, but nothing else is eqv.
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assert universe.are_equivalent(pkg_awk, pkg_mawk)
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assert not universe.are_equivalent(pkg_lintian, pkg_mawk)
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assert not universe.are_equivalent(pkg_lintian, pkg_perl)
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assert not universe.are_equivalent(pkg_mawk, pkg_perl)
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# Trivial test of the special case for adding and removing an essential package
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universe.remove_testing_binary(pkg_perl_base)
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universe.add_testing_binary(pkg_perl_base)
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universe.add_testing_binary(pkg_awk)
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assert universe.is_installable(pkg_lintian)
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def test_basic_essential_conflict(self):
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builder = new_pkg_universe_builder()
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pseudo_ess1 = builder.new_package('pseudo-essential1')
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pseudo_ess2 = builder.new_package('pseudo-essential2')
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essential_simple = builder.new_package('essential-simple').is_essential()
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essential_with_deps = builder.new_package('essential-with-deps').is_essential().\
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depends_on_any_of(pseudo_ess1, pseudo_ess2)
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conflict1 = builder.new_package('conflict1').conflicts_with(essential_simple)
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conflict2 = builder.new_package('conflict2').conflicts_with(pseudo_ess1, pseudo_ess2)
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conflict_installable1 = builder.new_package('conflict-inst1').conflicts_with(pseudo_ess1)
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conflict_installable2 = builder.new_package('conflict-inst2').conflicts_with(pseudo_ess2)
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universe = builder.build()
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assert universe.is_installable(essential_simple.pkg_id)
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assert universe.is_installable(essential_with_deps.pkg_id)
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assert universe.is_installable(conflict_installable1.pkg_id)
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assert universe.is_installable(conflict_installable2.pkg_id)
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assert not universe.is_installable(conflict1.pkg_id)
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assert not universe.is_installable(conflict2.pkg_id)
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for line in universe.stats.stats():
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print(line)
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assert universe.stats.conflicts_essential == 1
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def test_basic_simple_choice(self):
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builder = new_pkg_universe_builder()
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root_pkg = builder.new_package('root')
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conflicting1 = builder.new_package('conflict1')
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conflicting2 = builder.new_package('conflict2')
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bottom1_pkg = builder.new_package('bottom1').conflicts_with(conflicting1)
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bottom2_pkg = builder.new_package('bottom2').conflicts_with(conflicting2)
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pkg1 = builder.new_package('pkg1').depends_on(bottom1_pkg)
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pkg2 = builder.new_package('pkg2').depends_on(bottom2_pkg)
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root_pkg.depends_on_any_of(pkg1, pkg2)
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universe = builder.build()
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# The dependencies of "root" are not equivalent (if they were, we would trigger
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# an optimization, which takes another code path)
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assert not universe.are_equivalent(pkg1.pkg_id, pkg2.pkg_id)
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assert universe.is_installable(root_pkg.pkg_id)
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for line in universe.stats.stats():
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print(line)
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assert universe.stats.eqv_table_times_used == 0
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assert universe.stats.eqv_table_total_number_of_alternatives_eliminated == 0
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assert universe.stats.eqv_table_reduced_to_one == 0
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assert universe.stats.eqv_table_reduced_by_zero == 0
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def test_basic_simple_choice_deadend(self):
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builder = new_pkg_universe_builder()
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root_pkg = builder.new_package('root')
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bottom1_pkg = builder.new_package('bottom1').conflicts_with(root_pkg)
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bottom2_pkg = builder.new_package('bottom2').conflicts_with(root_pkg)
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pkg1 = builder.new_package('pkg1').depends_on(bottom1_pkg)
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pkg2 = builder.new_package('pkg2').depends_on(bottom2_pkg)
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root_pkg.depends_on_any_of(pkg1, pkg2)
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universe = builder.build()
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# The dependencies of "root" are not equivalent (if they were, we would trigger
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# an optimization, which takes another code path)
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assert not universe.are_equivalent(pkg1.pkg_id, pkg2.pkg_id)
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assert not universe.is_installable(root_pkg.pkg_id)
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for line in universe.stats.stats():
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print(line)
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assert universe.stats.eqv_table_times_used == 0
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assert universe.stats.eqv_table_total_number_of_alternatives_eliminated == 0
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assert universe.stats.eqv_table_reduced_to_one == 0
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assert universe.stats.eqv_table_reduced_by_zero == 0
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# This case is simple enough that the installability tester will assert it does not
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# need to recurse to reject the first option
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assert universe.stats.backtrace_restore_point_used == 0
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assert universe.stats.backtrace_last_option == 1
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def test_basic_simple_choice_opt_no_restore_needed(self):
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builder = new_pkg_universe_builder()
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conflicting = builder.new_package('conflict')
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root_pkg = builder.new_package('root').conflicts_with(conflicting)
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bottom1_pkg = builder.new_package('bottom1').conflicts_with(conflicting)
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bottom2_pkg = builder.new_package('bottom2').conflicts_with(conflicting)
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# These two packages have (indirect) conflicts, so they cannot trigger the
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# safe set optimization. However, since "root" already have the same conflict
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# it can use the "no restore point needed" optimization.
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pkg1 = builder.new_package('pkg1').depends_on(bottom1_pkg)
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pkg2 = builder.new_package('pkg2').depends_on(bottom2_pkg)
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root_pkg.depends_on_any_of(pkg1, pkg2)
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universe = builder.build()
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# The dependencies of "root" are not equivalent (if they were, we would trigger
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# an optimization, which takes another code path)
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assert not universe.are_equivalent(pkg1.pkg_id, pkg2.pkg_id)
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assert universe.is_installable(root_pkg.pkg_id)
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for line in universe.stats.stats():
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print(line)
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assert universe.stats.eqv_table_times_used == 0
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assert universe.stats.eqv_table_total_number_of_alternatives_eliminated == 0
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assert universe.stats.eqv_table_reduced_to_one == 0
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assert universe.stats.eqv_table_reduced_by_zero == 0
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assert universe.stats.backtrace_restore_point_used == 0
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assert universe.stats.backtrace_last_option == 0
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assert universe.stats.choice_resolved_without_restore_point == 1
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def test_basic_simple_choice_opt_no_restore_needed_deadend(self):
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builder = new_pkg_universe_builder()
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conflicting1 = builder.new_package('conflict1').conflicts_with('conflict2')
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conflicting2 = builder.new_package('conflict2').conflicts_with('conflict1')
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root_pkg = builder.new_package('root')
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bottom_pkg = builder.new_package('bottom').depends_on(conflicting1).depends_on(conflicting2)
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mid1_pkg = builder.new_package('mid1').depends_on(bottom_pkg)
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mid2_pkg = builder.new_package('mid2').depends_on(bottom_pkg)
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# These two packages have (indirect) conflicts, so they cannot trigger the
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# safe set optimization. However, since "root" already have the same conflict
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# it can use the "no restore point needed" optimization.
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pkg1 = builder.new_package('pkg1').depends_on(mid1_pkg)
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pkg2 = builder.new_package('pkg2').depends_on(mid2_pkg)
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root_pkg.depends_on_any_of(pkg1, pkg2)
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universe = builder.build()
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# The dependencies of "root" are not equivalent (if they were, we would trigger
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# an optimization, which takes another code path)
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assert not universe.are_equivalent(pkg1.pkg_id, pkg2.pkg_id)
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assert not universe.is_installable(root_pkg.pkg_id)
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for line in universe.stats.stats():
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print(line)
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assert universe.stats.eqv_table_times_used == 0
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assert universe.stats.eqv_table_total_number_of_alternatives_eliminated == 0
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assert universe.stats.eqv_table_reduced_to_one == 0
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assert universe.stats.eqv_table_reduced_by_zero == 0
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assert universe.stats.backtrace_restore_point_used == 0
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assert universe.stats.choice_resolved_without_restore_point == 0
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assert universe.stats.backtrace_last_option == 1
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def test_basic_choice_deadend_restore_point_needed(self):
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builder = new_pkg_universe_builder()
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root_pkg = builder.new_package('root')
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bottom1_pkg = builder.new_package('bottom1').depends_on_any_of('bottom2', 'bottom3')
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bottom2_pkg = builder.new_package('bottom2').conflicts_with(root_pkg)
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bottom3_pkg = builder.new_package('bottom3').depends_on_any_of('bottom1', 'bottom2')
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pkg1 = builder.new_package('pkg1').depends_on_any_of(bottom1_pkg, bottom2_pkg).conflicts_with('bottom3')
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pkg2 = builder.new_package('pkg2').depends_on_any_of(bottom2_pkg, bottom3_pkg).conflicts_with('bottom1')
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root_pkg.depends_on_any_of(pkg1, pkg2)
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universe = builder.build()
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# The dependencies of "root" are not equivalent (if they were, we would trigger
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# an optimization, which takes another code path)
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assert not universe.are_equivalent(pkg1.pkg_id, pkg2.pkg_id)
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assert not universe.is_installable(root_pkg.pkg_id)
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for line in universe.stats.stats():
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print(line)
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assert universe.stats.eqv_table_times_used == 0
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assert universe.stats.eqv_table_total_number_of_alternatives_eliminated == 0
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assert universe.stats.eqv_table_reduced_to_one == 0
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assert universe.stats.eqv_table_reduced_by_zero == 0
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# This case is simple enough that the installability tester will assert it does not
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# need to recurse to reject the first option
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assert universe.stats.backtrace_restore_point_used == 1
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assert universe.stats.backtrace_last_option == 1
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def test_corner_case_dependencies_inter_conflict(self):
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builder = new_pkg_universe_builder()
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root_pkg = builder.new_package('root').depends_on('conflict1').depends_on('conflict2')
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conflicting1 = builder.new_package('conflict1').conflicts_with('conflict2')
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conflicting2 = builder.new_package('conflict2').conflicts_with('conflict1')
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universe = builder.build()
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# They should not be eqv.
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assert not universe.are_equivalent(conflicting1.pkg_id, conflicting2.pkg_id)
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# "root" should not be installable and we should trigger a special code path where
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# the installability tester has both conflicting packages in its "check" set
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# Technically, we cannot assert we hit that path with this test, but we can at least
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# check it does not regress
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assert not universe.is_installable(root_pkg.pkg_id)
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def test_basic_choice_deadend_pre_solvable(self):
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builder = new_pkg_universe_builder()
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# This test is complicated by the fact that the inst-tester has a non-deterministic ordering.
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# To ensure that it becomes predictable, we have to force it to see the choice before
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# the part that eliminates it. In practise, this is easiest to do by creating a symmetric
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# graph where one solving one choice eliminates the other.
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root_pkg = builder.new_package('root')
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# These two packages are used to make options distinct; otherwise the eqv. optimisation will just
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# collapse the choices.
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nodep1 = builder.new_package('nodep1')
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nodep2 = builder.new_package('nodep2')
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path1a = builder.new_package('path1a').depends_on(nodep1).depends_on('end1')
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path1b = builder.new_package('path1b').depends_on(nodep2).depends_on('end1')
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path2a = builder.new_package('path2a').depends_on(nodep1).depends_on('end2')
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path2b = builder.new_package('path2b').depends_on(nodep2).depends_on('end2')
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builder.new_package('end1').conflicts_with(path2a, path2b)
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builder.new_package('end2').conflicts_with(path1a, path1b)
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root_pkg.depends_on_any_of(path1a, path1b).depends_on_any_of(path2a, path2b)
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universe = builder.build()
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assert not universe.is_installable(root_pkg.pkg_id)
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for line in universe.stats.stats():
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print(line)
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assert universe.stats.eqv_table_times_used == 0
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assert universe.stats.eqv_table_total_number_of_alternatives_eliminated == 0
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assert universe.stats.eqv_table_reduced_to_one == 0
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assert universe.stats.eqv_table_reduced_by_zero == 0
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# The following numbers are observed due to:
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# * Pick an option from (pathXa | pathXb)
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# * First option -> obviously unsolvable
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# * Undo and do "last option" on the remaining
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# * "last option" -> obviously unsolvable
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# * unsolvable
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assert universe.stats.backtrace_restore_point_used == 1
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assert universe.stats.backtrace_last_option == 1
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assert universe.stats.choice_presolved == 2
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def test_basic_choice_pre_solvable(self):
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builder = new_pkg_universe_builder()
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# This test is complicated by the fact that the inst-tester has a non-deterministic ordering.
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# To ensure that it becomes predictable, we have to force it to see the choice before
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# the part that eliminates it. In practise, this is easiest to do by creating a symmetric
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# graph where one solving one choice eliminates the other.
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root_pkg = builder.new_package('root')
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nodep1 = builder.new_package('nodep1').conflicts_with('path1b', 'path2b')
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nodep2 = builder.new_package('nodep2').conflicts_with('path1b', 'path2b')
|
|
|
|
end1 = builder.new_package('end1')
|
|
|
|
end2 = builder.new_package('end2')
|
|
|
|
|
|
|
|
path1a = builder.new_package('path1a').depends_on(nodep1).depends_on(end1)
|
|
|
|
path1b = builder.new_package('path1b').depends_on(nodep2).depends_on(end1)
|
|
|
|
|
|
|
|
path2a = builder.new_package('path2a').depends_on(nodep1).depends_on(end2)
|
|
|
|
path2b = builder.new_package('path2b').depends_on(nodep2).depends_on(end2)
|
|
|
|
|
|
|
|
root_pkg.depends_on_any_of(path1a, path1b).depends_on_any_of(path2a, path2b)
|
|
|
|
|
|
|
|
universe = builder.build()
|
|
|
|
|
|
|
|
assert universe.is_installable(root_pkg.pkg_id)
|
|
|
|
for line in universe.stats.stats():
|
|
|
|
print(line)
|
|
|
|
assert universe.stats.eqv_table_times_used == 0
|
|
|
|
assert universe.stats.eqv_table_total_number_of_alternatives_eliminated == 0
|
|
|
|
assert universe.stats.eqv_table_reduced_to_one == 0
|
|
|
|
assert universe.stats.eqv_table_reduced_by_zero == 0
|
|
|
|
|
|
|
|
# After its first guess, the tester can pre-solve remaining choice
|
|
|
|
assert universe.stats.backtrace_restore_point_used == 0
|
|
|
|
assert universe.stats.choice_presolved == 1
|
|
|
|
|
|
|
|
def test_optimisation_simple_full_eqv_reduction(self):
|
|
|
|
builder = new_pkg_universe_builder()
|
|
|
|
root_pkg = builder.new_package('root')
|
|
|
|
conflicting = builder.new_package('conflict')
|
|
|
|
bottom1_pkg = builder.new_package('bottom1').conflicts_with(conflicting)
|
|
|
|
# Row 1 is simple enough that it collapse into a single option immediately
|
|
|
|
# (Ergo eqv_table_reduced_to_one == 1)
|
|
|
|
row1 = ['pkg-%s' % x for x in range(1000)]
|
|
|
|
|
|
|
|
root_pkg.depends_on_any_of(*row1)
|
|
|
|
for pkg in row1:
|
|
|
|
builder.new_package(pkg).depends_on(bottom1_pkg)
|
|
|
|
universe = builder.build()
|
|
|
|
|
|
|
|
pkg_row1 = builder.pkg_id(row1[0])
|
|
|
|
|
|
|
|
# all items in a row are eqv.
|
|
|
|
for pkg in row1:
|
|
|
|
assert universe.are_equivalent(builder.pkg_id(pkg), pkg_row1)
|
|
|
|
|
|
|
|
assert universe.is_installable(root_pkg.pkg_id)
|
|
|
|
for line in universe.stats.stats():
|
|
|
|
print(line)
|
|
|
|
assert universe.stats.eqv_table_times_used == 1
|
|
|
|
assert universe.stats.eqv_table_total_number_of_alternatives_eliminated == 999
|
|
|
|
assert universe.stats.eqv_table_reduced_to_one == 1
|
|
|
|
|
|
|
|
def test_optimisation_simple_partial_eqv_reduction(self):
|
|
|
|
builder = new_pkg_universe_builder()
|
|
|
|
root_pkg = builder.new_package('root')
|
|
|
|
conflicting = builder.new_package('conflict')
|
|
|
|
another_pkg = builder.new_package('another-pkg')
|
|
|
|
bottom1_pkg = builder.new_package('bottom1').conflicts_with(conflicting)
|
|
|
|
# Row 1 is simple enough that it collapse into a single option immediately
|
|
|
|
# but due to "another_pkg" the entire choice is only reduced into two
|
|
|
|
row1 = ['pkg-%s' % x for x in range(1000)]
|
|
|
|
|
|
|
|
root_pkg.depends_on_any_of(another_pkg, *row1)
|
|
|
|
for pkg in row1:
|
|
|
|
builder.new_package(pkg).depends_on(bottom1_pkg)
|
|
|
|
universe = builder.build()
|
|
|
|
|
|
|
|
pkg_row1 = builder.pkg_id(row1[0])
|
|
|
|
|
|
|
|
# all items in a row are eqv.
|
|
|
|
for pkg in row1:
|
|
|
|
assert universe.are_equivalent(builder.pkg_id(pkg), pkg_row1)
|
|
|
|
|
|
|
|
assert universe.is_installable(root_pkg.pkg_id)
|
|
|
|
for line in universe.stats.stats():
|
|
|
|
print(line)
|
|
|
|
assert universe.stats.eqv_table_times_used == 1
|
|
|
|
assert universe.stats.eqv_table_total_number_of_alternatives_eliminated == 999
|
|
|
|
assert universe.stats.eqv_table_reduced_to_one == 0
|
|
|
|
|
|
|
|
def test_optimisation_simple_zero_eqv_reduction(self):
|
|
|
|
builder = new_pkg_universe_builder()
|
|
|
|
root_pkg = builder.new_package('root')
|
|
|
|
conflicting1 = builder.new_package('conflict1')
|
|
|
|
conflicting2 = builder.new_package('conflict2')
|
|
|
|
bottom1_pkg = builder.new_package('bottom1').conflicts_with(conflicting1)
|
|
|
|
bottom2_pkg = builder.new_package('bottom2').conflicts_with(conflicting2)
|
|
|
|
|
|
|
|
# To trigger a failed reduction, we have to create eqv. packages and ensure that only one
|
|
|
|
# of them are in testing. Furthermore, the choice has to remain, so we create two pairs
|
|
|
|
# of them
|
|
|
|
pkg1_v1 = builder.new_package('pkg1', version='1.0-1').depends_on(bottom1_pkg)
|
|
|
|
pkg1_v2 = builder.new_package('pkg1', version='2.0-1').depends_on(bottom1_pkg).not_in_testing()
|
|
|
|
pkg2_v1 = builder.new_package('pkg2', version='1.0-1').depends_on(bottom2_pkg)
|
|
|
|
pkg2_v2 = builder.new_package('pkg2', version='2.0-1').depends_on(bottom2_pkg).not_in_testing()
|
|
|
|
|
|
|
|
root_pkg.depends_on_any_of(pkg1_v1, pkg1_v2, pkg2_v1, pkg2_v2)
|
|
|
|
|
|
|
|
universe = builder.build()
|
|
|
|
|
|
|
|
# The packages in the pairs are equivalent, but the two pairs are not
|
|
|
|
assert universe.are_equivalent(pkg1_v1.pkg_id, pkg1_v2.pkg_id)
|
|
|
|
assert universe.are_equivalent(pkg2_v1.pkg_id, pkg2_v2.pkg_id)
|
|
|
|
assert not universe.are_equivalent(pkg1_v1.pkg_id, pkg2_v1.pkg_id)
|
|
|
|
|
|
|
|
assert universe.is_installable(root_pkg.pkg_id)
|
|
|
|
for line in universe.stats.stats():
|
|
|
|
print(line)
|
|
|
|
assert universe.stats.eqv_table_times_used == 1
|
|
|
|
assert universe.stats.eqv_table_total_number_of_alternatives_eliminated == 0
|
|
|
|
assert universe.stats.eqv_table_reduced_to_one == 0
|
|
|
|
assert universe.stats.eqv_table_reduced_by_zero == 1
|
|
|
|
|
|
|
|
def test_solver_recursion_limit(self):
|
|
|
|
builder = new_pkg_universe_builder()
|
|
|
|
recursion_limit = 200
|
|
|
|
pkg_limit = recursion_limit + 20
|
|
|
|
orig_limit = sys.getrecursionlimit()
|
|
|
|
pkgs = [builder.new_package('pkg-%d' % i) for i in range(pkg_limit)]
|
|
|
|
|
|
|
|
for i, pkg in enumerate(pkgs):
|
|
|
|
# Intentionally -1 for the first package (wrap-around)
|
|
|
|
ni = i - 1
|
|
|
|
pkg.not_in_testing()
|
|
|
|
pkg.depends_on(pkgs[ni])
|
|
|
|
|
|
|
|
try:
|
|
|
|
sys.setrecursionlimit(recursion_limit)
|
|
|
|
universe = builder.build()
|
|
|
|
groups = []
|
|
|
|
|
|
|
|
for pkg in pkgs:
|
|
|
|
group = (pkg.pkg_id.package_name, {pkg.pkg_id}, set())
|
|
|
|
groups.append(group)
|
|
|
|
|
|
|
|
expected = {g[0] for g in groups}
|
|
|
|
actual = universe.solve_groups(groups)
|
|
|
|
assert actual
|
|
|
|
assert expected == set(actual[0])
|
|
|
|
assert len(actual) == 1
|
|
|
|
finally:
|
|
|
|
sys.setrecursionlimit(orig_limit)
|
|
|
|
|
|
|
|
def test_solver_simple_scc(self):
|
|
|
|
builder = new_pkg_universe_builder()
|
|
|
|
|
|
|
|
# SCC 1
|
|
|
|
pkga = builder.new_package('pkg-a').not_in_testing()
|
|
|
|
pkgb = builder.new_package('pkg-b').not_in_testing()
|
|
|
|
pkgc = builder.new_package('pkg-c').not_in_testing()
|
|
|
|
|
|
|
|
# SSC 2
|
|
|
|
pkgd = builder.new_package('pkg-d').not_in_testing()
|
|
|
|
pkge = builder.new_package('pkg-e').not_in_testing()
|
|
|
|
pkgf = builder.new_package('pkg-f').not_in_testing()
|
|
|
|
pkgg = builder.new_package('pkg-g').not_in_testing()
|
|
|
|
pkgh = builder.new_package('pkg-h').not_in_testing()
|
|
|
|
|
|
|
|
# SSC 3
|
|
|
|
pkgi = builder.new_package('pkg-i').not_in_testing()
|
|
|
|
|
|
|
|
# SSC 1 dependencies
|
|
|
|
pkga.depends_on(pkgb)
|
|
|
|
pkgb.depends_on(pkgc).depends_on(pkgd)
|
|
|
|
pkgc.depends_on(pkga).depends_on(pkge)
|
|
|
|
|
|
|
|
# SSC 2 dependencies
|
|
|
|
pkgd.depends_on(pkgf)
|
|
|
|
pkge.depends_on(pkgg).depends_on(pkgd)
|
|
|
|
pkgf.depends_on(pkgh)
|
|
|
|
pkgg.depends_on(pkgh)
|
|
|
|
pkgh.depends_on(pkge).depends_on(pkgi)
|
|
|
|
|
|
|
|
universe = builder.build()
|
|
|
|
expected = [
|
|
|
|
# SSC 3 first
|
|
|
|
{pkgi.pkg_id.package_name},
|
|
|
|
# Then SSC 2
|
|
|
|
{pkgd.pkg_id.package_name, pkge.pkg_id.package_name, pkgf.pkg_id.package_name,
|
|
|
|
pkgg.pkg_id.package_name, pkgh.pkg_id.package_name},
|
|
|
|
# Finally SSC 1
|
|
|
|
{pkga.pkg_id.package_name, pkgb.pkg_id.package_name, pkgc.pkg_id.package_name},
|
|
|
|
]
|
|
|
|
groups = []
|
|
|
|
for ssc in expected:
|
|
|
|
for node in ssc:
|
|
|
|
groups.append((node, {builder.pkg_id(node)}, {}))
|
|
|
|
|
|
|
|
actual = [set(x) for x in universe.solve_groups(groups)]
|
|
|
|
print("EXPECTED: %s" % str(expected))
|
|
|
|
print("ACTUAL : %s" % str(actual))
|
|
|
|
assert expected == actual
|
|
|
|
|
|
|
|
def test_solver_no_scc_stack_bug(self):
|
|
|
|
"""
|
|
|
|
This whitebox test is designed to trigger a bug in Tarjan's algorithm
|
|
|
|
if you omit the "w is on stack of points" check from the pseudo code
|
|
|
|
(or it is wrong). It makes tons of assumptions about how compute_scc
|
|
|
|
works, so it is very sensitive to even minor tweaks.
|
|
|
|
|
|
|
|
There is no strongly-connected component in this test, but if we
|
|
|
|
trigger the bug, the algorithm will think there is one.
|
|
|
|
"""
|
|
|
|
|
|
|
|
graph = OrderedDict()
|
|
|
|
|
|
|
|
graph['A'] = {
|
|
|
|
'before': ['C', 'B'],
|
|
|
|
'after': ['A0'],
|
|
|
|
}
|
|
|
|
graph['B'] = {
|
|
|
|
'before': ['F'],
|
|
|
|
'after': ['A'],
|
|
|
|
}
|
|
|
|
graph['C'] = {
|
|
|
|
'before': ['E', 'D'],
|
|
|
|
'after': ['A'],
|
|
|
|
}
|
|
|
|
graph['D'] = {
|
|
|
|
'before': [],
|
|
|
|
'after': ['C']
|
|
|
|
}
|
|
|
|
graph['E'] = {
|
|
|
|
'before': ['B'],
|
|
|
|
'after': ['C']
|
|
|
|
}
|
|
|
|
graph['F'] = {
|
|
|
|
'before': [],
|
|
|
|
'after': ['B']
|
|
|
|
}
|
|
|
|
graph['A0'] = {
|
|
|
|
'before': ['A0'],
|
|
|
|
'after': []
|
|
|
|
}
|
|
|
|
|
|
|
|
# We also assert that the order is correct to ensure that
|
|
|
|
# nodes were visited in the order we expected (the bug is
|
|
|
|
# visit order sensitive).
|
|
|
|
expected = [
|
|
|
|
('F',),
|
|
|
|
('B',),
|
|
|
|
('D',),
|
|
|
|
('E',),
|
|
|
|
('C',),
|
|
|
|
('A',),
|
|
|
|
('A0',)
|
|
|
|
]
|
|
|
|
|
|
|
|
actual = compute_scc(graph)
|
|
|
|
print("EXPECTED: %s" % str(expected))
|
|
|
|
print("ACTUAL : %s" % str(actual))
|
|
|
|
assert expected == actual
|
|
|
|
|
|
|
|
if __name__ == '__main__':
|
|
|
|
unittest.main()
|
|
|
|
|