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Use any() in tpu o-o-d checks rather than throwaway lists

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The test only needs to consider whether any binaries exist on a given
arch, not how many of them there are (or indeed which binaries they are)

Signed-off-by: Adam D. Barratt <adam@adam-barratt.org.uk>
This commit is contained in:
Adam D. Barratt 2013-02-06 19:09:04 +00:00
parent 25cc2c3b36
commit acec4ff6e3
1 changed files with 5 additions and 5 deletions
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britney.py
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@ -1371,17 +1371,17 @@ class Britney(object):
# if the package in testing has no binaries on this
# architecture, it can't be out-of-date
if (len([x for x in self.sources["testing"][src][BINARIES]
if x.endswith("/"+arch) and self.binaries["testing"][arch][0][x.split("/")[0]][ARCHITECTURE] != 'all' ]) == 0):
if not any(x for x in self.sources["testing"][src][BINARIES]
if x.endswith("/"+arch) and self.binaries["testing"][arch][0][x.split("/")[0]][ARCHITECTURE] != 'all'):
continue
# if the (t-)p-u package has produced any binaries on
# this architecture then we assume it's ok. this allows for
# uploads to (t-)p-u which intentionally drop binary
# packages
if (len([x for x in self.binaries[suite][arch][0].values() \
if x[SOURCE] == src and x[SOURCEVER] == source_u[VERSION] and \
x[ARCHITECTURE] != 'all' ]) > 0):
if any(x for x in self.binaries[suite][arch][0].values() \
if x[SOURCE] == src and x[SOURCEVER] == source_u[VERSION] and \
x[ARCHITECTURE] != 'all'):
continue
if suite == 'tpu':